0=-16x^2-70x+49

Solution for 0=-16x^2-70x+49 equation:

0=-16x^2-70x+49

We move all terms to the left:

0-(-16x^2-70x+49)=0

We add all the numbers together, and all the variables

-(-16x^2-70x+49)=0

We get rid of parentheses

16x^2+70x-49=0

a = 16; b = 70; c = -49;
Δ = b2-4ac
Δ = 702-4·16·(-49)
Δ = 8036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8036}=\sqrt{196*41}=\sqrt{196}*\sqrt{41}=14\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-14\sqrt{41}}{2*16}=\frac{-70-14\sqrt{41}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+14\sqrt{41}}{2*16}=\frac{-70+14\sqrt{41}}{32}
$